Re: Yielding across lua_load

[Patrick Donnelly <batrick@...>]

On Thu, Oct 8, 2015 at 1:48 PM, Soni L. <fakedme@gmail.com> wrote:
>
>
> On 08/10/15 02:21 PM, Patrick Donnelly wrote:
>>
>> On Thu, Oct 8, 2015 at 7:55 AM, Soni L. <fakedme@gmail.com> wrote:
>>>
>>> Is it possible to yield across lua_load?
>>>
>>> --
>>> Disclaimer: these emails may be made public at any given time, with or
>>> without reason. If you don't agree with this, DO NOT REPLY.
>>
>> $ lua
>> Lua 5.3.1  Copyright (C) 1994-2015 Lua.org, PUC-Rio
>>>
>>> coroutine.wrap(function() assert(load(function() coroutine.yield("a = 1")
>>> end)) end)()
>>
>> stdin:1: stdin:1: attempt to yield across a C-call boundary
>> stack traceback:
>>          [C]: in ?
>>          stdin:1: in main chunk
>>          [C]: in ?
>>
> I said lua_load.
>
> load() uses lua_call internally (not lua_callk)

The documentations says:

"To avoid this kind of problem, Lua raises an error whenever it tries
to yield across an API call, except for three functions:
lua_yieldk,lua_callk, and lua_pcallk. All those functions receive a
continuation function (as a parameter named k) to continue execution
after a yield."

http://www.lua.org/manual/5.3/manual.html#4.7

[I'm not going to check if lua_load will throw an error if you try to
yield across it.] The documentation requires that a yieldable API must
also receive a continuation function. lua_load has no argument for a
continuation function.

-- 
Patrick Donnelly