Hello everyone,
my knowledge about regular expressions is very limited, so I'm struggling with this
problem:
Given 2 strings
s1 = '/foo/:bar/oof/:rab'
s2 = '/foo/lua/oof/rocks'
I would like to produce the following information
1) If they match (these two above should match)
2) a table holding the values of 's2' in with the corresponding name in 's1'
In this case we would have: { bar = "lua", rab = "rocks" }
I think this algorithm solves it, but I cant figure how to implement it:
a) store the placeholders ':' indexes as KEYS of a table, and the respective VALUES being
the name of these placeholders
example with s1:
local aux1 = { "6" = "bar", "15" = "rab" }
b) with the keys of 'aux1' fetched as indexes, extract the values of 's2'
into another table
local aux2 = {"6" = "lua", "15" = "rocks}
c) finally merge them two into one table (this one is easy :P)
{ bar = "lua", rab = "rocks" }
