回复： help with string:match

[张睿 <zrui16@...>]

Something like (not tested, and you need a split() implementation):

t1 = split(s1, '/') --> {'', 'foo', ':bar', 'oof', ':rab'}

t2 = split(s2, '/') --> {'', 'foo', 'lua', 'oof', 'rocks'}

r = {}

if #t1 ~= #t2 then

  return false, "not match"

end

for i = 1, #t1 do

  if t1[i]:sub(1, 1) == ':' then

    r[t1[i]:sub(2)] = t2[i]

  elseif t1[i] ~= t2[i] then

    return false, "not match"

  end

end

return r

-------- 原始邮件 --------

发件人： Pablo Botelho

日期:2015-03-01 21:04 (GMT+08:00)

收件人： Lua mailing list

主题： help with string:match

Hello everyone,

    my knowledge about regular expressions is very limited, so I'm struggling with this problem:

Given 2 strings

s1 = '/foo/:bar/oof/:rab'

s2 = '/foo/lua/oof/rocks'

I would like to produce the following information

1) If they match (these two above should match)

2) a table holding the values of 's2' in with the corresponding name in 's1'
In this case we would have: { bar = "lua", rab = "rocks" }

I think this algorithm solves it, but I cant figure how to implement it:

a) store the placeholders ':' indexes as KEYS of a table, and the respective VALUES being the name of these placeholders

 example with s1:
local aux1 = { "6" = "bar", "15" = "rab" }

b) with the keys of 'aux1' fetched as indexes, extract the values of 's2'
into another table
local aux2 = {"6" = "lua", "15" = "rocks}

c) finally merge them two into one table (this one is easy :P)
{ bar = "lua", rab = "rocks" }

Thank you!