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2014-12-15 4:49 GMT+02:00 Sam Putman <atmanistan@gmail.com>:

> The grammar, as written, will not loop, and the compiler can reason through
> the call chain, just like we do, to confirm that.

In this case, it can. But a mechanism that can in general determine whether
a given grammar will terminate for all input --- didn't Alan Turing prove that
to be impossible?