Re: confusion about an exercise in programming lua 3rd

["Thiago L." <fakedme@...>]

On 25/11/14 10:57 AM, Kang Hu wrote:
> In Programming in Lua, Third Edition:
>
> Exercise 2.6: Assume the following code:
> a = {};
> a.a = a
> 1. What would be the value of a.a.a.a ? Is any a in that sequence somehow
> different from the others?
> 2. Now, add the next line to the previous code:
> a.a.a.a = 3
> What would be the value of a.a.a.a now?
>
> my reasoning is
> 1. a.a.a.a = ((a.a).a).a = (a.a).a = a.a = a
> 2. with the the previous reasoning, 'a' should be 3.
>      but actually, 'a.a' equals 3 and 'a' is a table.
> why?
a = {}
_G.a.a = a
a.a.a.a = 3
print(_G.a.a)

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