Re: Little fun with vararg

[Roberto Ierusalimschy <roberto@...>]

>   I don't know.  This
> 
> 	x = 5
> 	function F(...)
> 	  return F(x,...)
> 	end
> 
> 	print(F())
> 
> is taking an awful long time to fail.

I believe this is O(n^2), as each new call copies all accumulated
arguments. Change your function to this and you will see the
slowdown:

local x = 0
function F(...)
  x = x + 1
  print(x)
  return F(x,...)
end

print(F())

(The stack limit is 100 000...)

-- Roberto