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On 24 Jun 2014 13:52, "Lucas" <cad.lua@lucasjr.nospammail.net> wrote:
>
> Ok, my intention was to write such a function
>
> function modulus(n, d) return n - (q = math.floor(n/d)) * d, q; end
>
> is there any means to write it down just as simple?
>
> r, q = modulus(10, 3)
>

Sticking with your existing technique:
function modulus(n, d)
    local q = math.floor(n/d)
    return n - q * d, q
end

Using the modulus operator (I'm pretty sure this is correct):
function modulus(n, d)
    return n % d, math.floor(n/d)
end

Regards,
Choonster