Re: Matching non-escapped quote with Lua pattern

[Andrew Starks <andrew.starks@...>]

On Monday, March 3, 2014, Philipp Janda <siffiejoe@gmx.net> wrote:
> Am 03.03.2014 19:34 schröbte Andrew Starks:
> > I'm having trouble finding a pattern that works for finding an
> > unescaped quote in a string. So:
> >
> > [[\']] should not match
> >
> > [[']] should match
> >
> > I can get it to work with  '([^%\\]")' , except at the beginning of the string.
>
> You could put a dummy character at the beginning of the string ...
>
> My suggestion:
>
>     local function qfind( s )
>       local ok, a, b = string.match( " "..s, "[^\\](\\*)%1()[\"']()" )
>       if ok then
>         return a-1, b-1
>       end
>       return nil
>     end
>
> (But if you write an extra function for matching, you could as well try the two different patterns and save the temporary string ...)
>
> > -Andrew
>
> Philipp

Thank you, both. Enrico's solution is the one that I had in place. 

I had failed to grasp that "any character that is not" means that there must be a character.  

-Andrew