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> > That may not do what is expected, because it involves 
> > implementation-defined behavior:
> > 
> > Signed and unsigned integers [...]  When an integer is
> > demoted to a signed integer with smaller size, or an unsigned
> > integer is converted to its corresponding signed integer, if the
> > value cannot be represented the result is implementation-defined.
> If I remember right, you can work around this with a memcpy() from the
> unsigned variable to the signed variable.

Before trying to solve a problem, let us be sure there is a
problem. Have anyone ever used a C implementation where the conversion
from unsigned int to int did not have the "expected" behavior (keep the
bits unchanged)?

-- Roberto