Re: Cannot dynamically load executable

[Drake Wilson <drake@...>]

Quoth Matt Eisan <mattjeisan@gmail.com>, on 2013-04-24 20:42:40 -0400:
> I have attached the code I am using, and I compile with GCC using g++
> dir.cpp -o test.so -llua
[...]
> int main() {
> 	return 0;
> }

No, you want to create a shared library, not a main executable file.  Use g++
-shared and get rid of main(), to start with.  Nor, I think, will it work with
the name 'test.so' but an entrypoint function name of luaopen_mylib; the
expected load name should match the luaopen_* entrypoint and the .so basename,
as in foo.so loaded with require('foo') defining the C function luaopen_foo.

Also, all of the functions you're planning to cast to lua_CFunction (such as
l_dir), as well as the luaopen_* entrypoint, should be extern "C", if I'm not
mistaken.  (You'll also want to consider exceptions if you're interfacing to
C++, but that can be later.)

   ---> Drake Wilson