Re: LuaSocket nonblocking receive() semantics

[Flemming Madsen <lua@...>]

Well thanks. I had looked at settimeout(), but the crucial documentation part was:

    Also, after the error message, the function returns the partial result of the transmission.

   

The following ugly hack fulfills my needs then. 

Thanks again. /Flemming

debug.getregistry()["tcp{client}"].__index.read = 

function(sock, pattern, ...)

   local str, err, part = sock:receive(pattern, ...)

   if not str and err == "timeout" then

      str = part

   end

   return str, err, part

end

On Thu, Mar 15, 2012 at 8:40 PM, Matthew Wild <mwild1@gmail.com> wrote:

Are you missing conn:settimeout(0)? If not, do you have a test case
where receive() blocks?