Re: [LuaJIT] ffi work if not a 'local'

[sduclos <sduclos.cairo@...>]

Ha boys, this is embarrassing :)

Thanks,



On Sat, Jan 7, 2012 at 12:20 PM, Duncan Cross <duncan.cross@gmail.com> wrote:
> On Sat, Jan 7, 2012 at 5:13 PM, sduclos <sduclos.cairo@gmail.com> wrote:
>> Hi,
>>
>> Just to report that LuaJIT-2.0.0 (beta9 & git) work if 'ffi' is not a
>> 'local' variable
>>
>> The tutorial say:
>>
>>> local ffi = require("ffi")
>>
>> but a printf(ffi) return 'nil'
>>
>>
>> However if 'local' is absent ffi work as advertise:
>>
>> $  ./luajit
>> LuaJIT 2.0.0-beta9 -- Copyright (C) 2005-2011 Mike Pall. http://luajit.org/
>> JIT: ON CMOV SSE2 SSE3 AMD fold cse dce fwd dse narrow loop abc fuse
>>> local ffi = require("ffi")
>>> print(ffi)
>> nil
>>> ffi = require("ffi")
>>> print(ffi)
>> table: 0x405faf18
>>>
>> ...
>
> Every line you write at the interactive prompt is compiled and run as
> its own chunk, with its own local variables. This is the same in
> standard Lua. Try this at the interactive prompt:
>
>  > local a = 3
>  > print(a)
>
> It makes local variables when using the interactive prompt pretty
> useless in general, at least for single-line stuff.
>
> -Duncan
>