Re: luajit bugs with big number. malformed number near '0x100000000000000000000'

[zhiguo zhao <zhaozg@...>]

Your means ms makes this bug?

I not care below with lua 5.1.4,

> > i = 0x100000000000000   -- with 8 bytes, 64 bits

> > print(i)
> 4294967295

But I care below with luajit 2b8 head

Lua 5.1.4 Support  64bits int, but luajit support only 32bits.

D:\work\mod_luaex\etc>\work\luajit-2.0\bin\luajit.exe

LuaJIT 2.0.0-beta8 -- Copyright (C) 2005-2011 Mike Pall. http://luajit.org/

JIT: ON CMOV SSE2 SSE3 SSE4.1 fold cse dce fwd dse narrow loop abc fuse

> print(0x1000000000)

stdin:1: malformed number near '0x1000000000'

> print(0x10000000)  only -- with 4 bytes, 32 bits

268435456

>

I hope not to require other math libs support 64bits integer.

2011/11/20 Mike Pall <mikelu-1111@mike.de>

zhiguo zhao wrote:
> Why? integer too long?
>
> windows 32bits, msvc2008 build.

Support for hexadecimal floating-point numbers is a C99 feature.
MSVC is not C99-compliant, please complain to Microsoft.

> Lua 5.1.4  Copyright (C) 1994-2008 Lua.org, PUC-Rio
> > i = 0x100000000000000
> > print(i)
> 4294967295

Note that you're getting a wrong result with plain Lua. Would you
rather silently get a wrong result or a proper error message?

--Mike