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- Subject: Re: SV: pack/unpack
- From: David Kastrup <dak@...>
- Date: Wed, 15 Jun 2011 17:01:43 +0200
Dirk Laurie <firstname.lastname@example.org> writes:
> On Wed, Jun 15, 2011 at 03:50:00PM +0200, Fredrik Widlund wrote:
>> Ok, thank you! So in a list of expr a vararg is evaluated to the first
>> element of the vararg unless last in the list.
>> May I ask why this is?
> Suppose f and g both return a variable number of values.
> a,b,c = f(),g()
> At present we know that a will get the first value from f,
> b the first value from g, c the second value from g.
> If the rule was not there, we would not know whether b will get
> the second value from f or the first value from g, etc.
Actually, you would not even know whether a gets its value from g, since
f could just do "return", returning no values at all.