Re: [ANN] LuaClassBasedCall 1.0

[Александр Мельников <a.melnikov69@...>]

Hello Patrick,
I found small bug, in lgencall.hpp.
In:
template<class T> inline void Output::GetVector(lua_State* L, int idx) const
{
vector<T>* v = (vector<T>*)PointerValue;
luaL_checktype(L, idx, LUA_TTABLE);
size_t len = lua_objlen(L, idx);
int top = lua_gettop(L);
for(size_t i=0;i<len;i++)
{
 lua_pushinteger(L, i+1);
 lua_gettable(L, idx);
 T value;
 Output output(value);
---  output.Get(L, -1);
+++ output.Get(L, idx+1);
 v->push_back(value);
 lua_settop(L, top);
}
}

It fix allow use std::vector< std::vector< T ....
Instead code throw an exception: Lua exception: attempt to index a number 
value

My example works after this fix.

#include <iostream>
#define LCBC_USE_CSL 1
#include "lgencall.hpp"

using namespace lua;
typedef std::vector<std::vector<int> > vvs_type;
typedef std::vector<int> vs_type;
int main(int argc, char* argv[])
{
   Lua L;  // The constructor will open a new Lua state and include 
libraries
   try
   {
       vvs_type vvs;
       L.ExceptCall("mytable = {{1,2},{3,4},{5,6}}; return mytable", 
Outputs(Output(vvs)));
       for(vvs_type::const_iterator oit=vvs.begin();
           oit!=vvs.end();
          ++oit)
           {
            for(vs_type::const_iterator it=(*oit).begin();
                 it!=(*oit).end();
                ++it)
                std::cout << *it << " ";
            std::cout << std::endl;
           }
      vs_type vs;
       L.ExceptCall("mytable = {10,20,30,40,50,60}; return mytable", 
Outputs(Output(vs)));
            for(vs_type::const_iterator it=vs.begin();
                 it!=vs.end();
                ++it)
                std::cout << *it << " ";
            std::cout << std::endl;
   }
   catch(Error err)
   {
       printf("Lua exception: %s\n", (const char*)err);
   }
} // The Lua state is closed by the destructor



Alexander.