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2011/3/10 Jayanth Acharya <jayachar88@gmail.com>:
This is the same as string.match(_NAME, "^[^%.]+"), which assumes the> Probably as a result of adopting a leap-frogging (instead of a thorough)
> approach to learning Lua, am not quite able to figure out what this segment
> of code does/means, and a google search didn't yeild much.
>
> local struct = require(_NAME:match("^[^%.]+"))
> local name = (...):gsub('%.[^%.]+$', '')
>
> This is from the vstruct basic.lua example. What does the _NAME:match() do ?
_NAME variable (global unless defined as local above in the script) is
a string, and it returns everything up to the first dot character in
that string. For example if _NAME is "foo.bar.baz", then struct would
be "foo".
... at the global scope refers to the parameters passed to the current
> What does "(...):gsub(pattern...)" do ?
script. If this is a module, "require" will pass the module name as
only parameter. This is the same as :
local modname = ...
local name = string.gsub(modname, '%.[^%.]+$', '')
And that would remove the last part of a dot-delimited sequence of
sub-strings. For example if modname=="foo.bar.baz", then name would be
"foo.bar".