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When you load the file in your app, do you already have the absolute
path?  If so, why not just make a global var with the directory in it?


You could do something like:

dofile(script.path.."/other_file.lua")

wes




On Thu, Feb 24, 2011 at 2:49 AM, Gaspard Bucher <gaspard@teti.ch> wrote:
> I have found a better solution with debug.getinfo:
> -- Find the source of the current file.
> function lk.source(level)
>   local level = level or 0
>   return debug.getinfo(level + 2).source
> end
> -------------------------------- lk.dir()
> -- Find the directory of the current file.
> function lk.dir(level)
>   local level = level or 0
>   local source = string.gsub(lk.source(level+1), '/[^/]+$', '')
>   return string.match(source, '^@(.*)$')
> end
>
> On Thu, Feb 24, 2011 at 11:06 AM, Gaspard Bucher <gaspard@teti.ch> wrote:
>>
>> Hi list,
>> To ease installation and improve stability when moving scripts around, I
>> need to load Lua files relative to the current file. What I basically need
>> is a local FILE_DIR variable set to the file's directory.
>> My solution involves inserting a "local FILE_DIR" at the top of the files
>> on file load but I wonder if there is a better way to solve this problem...
>> Gaspard
>> Typical usage script:
>> ================ foo_test.lua
>> require 'lubyk'
>> FILE_DIR = FILE_DIR or lfs.currentdir() -- in case the file is run alone
>> ...
>> function should.do_this_and_that()
>>   local fixture = fixture.readall(FILE_DIR, 'xxx.txt')
>> end
>> ================
>> ================ lk.dofile
>> function lk.dofile(filepath)
>>   local abs_path = filepath
>>   local cur_path = lfs.currentdir()
>>   if not string.match(abs_path, '^/') then
>>     abs_path = string.format('%s/%s', cur_path, filepath)
>>   end
>>   ----------- FILE_DIR hack -----------
>>   local code_str = string.format("local FILE_DIR = '%s';%s",
>> string.gsub(abs_path, '/[^/]+$', ''), lk.readall(abs_path))
>>   local code = assert(loadstring(code_str))
>>   code()
>> end
>> ================
>