Re: How to get the directory of the current executed file?

[Norman Clarke <norman@...>]

On Fri, Jan 14, 2011 at 07:46, Tang Daogang <daogangtang@gmail.com> wrote:
>
>
> On Fri, Jan 14, 2011 at 2:28 PM, steve donovan <steve.j.donovan@gmail.com>
> wrote:
>>
>> On Fri, Jan 14, 2011 at 8:26 AM, steve donovan
>> <steve.j.donovan@gmail.com> wrote:
>> > The lfs module from LuaFileSystem is the best known method:
>>
>> Nah, scratch that - sorry I have not had my tea.
>>
>> You can look at arg[0] for the script name, and work from there.
>>
>> Or get the debug information:
>>
>> function script_path()
>>    -- remember to strip off the starting @
>>    return debug.getinfo(2, "S").source:sub(2)
>> end
>>
>> print(script_path())
>>
> The debug library seems works on that. Thank you. I find it.

Not sure if you found this already, but I think what you're looking
for is something more like:

debug.getinfo(1).source:match("@(.*)$")

which will give you the current file where the call to debug.getinfo
is being made, regardless of which file is actually being executed.