Re: how to store multi return value provisionally?

[Peter Cawley <lua@...>]

On Mon, Dec 20, 2010 at 1:43 PM, starwing <weasley.wx@gmail.com> wrote:
> 2010/12/20 Axel Kittenberger <axkibe@gmail.com>:
>> Just put em into a table:
>>
>>> function r5() return 1, 2, 3, 4, 5 end
>>> re = {r5()}
>>> for k, v in ipairs(re) do print(k, v) end
>> 1       1
>> 2       2
>> 3       3
>> 4       4
>> 5       5
>>
>>
>> On Mon, Dec 20, 2010 at 2:23 PM, starwing <weasley.wx@gmail.com> wrote:
>>> 2010/12/20 Michal Kottman <k0mpjut0r@gmail.com>:
>>>> On Mon, 2010-12-20 at 20:48 +0800, starwing wrote:
>>>>> i.e. i want to do that:
>>>>>
>>>>> ??? = coroutine.resume(...)
>>>>> if ???[1] then
>>>>>      --- do something with ???[1...]
>>>>> else
>>>>>      --- do something with ???[1...]
>>>>> end
>>>>>
>>>>> but I don't want to use table, I just wonder it's possible to
>>>>> implement it just operate the multi-values itself.
>>>>
>>>> Create locals from them. For example, if your thread yields 3 values:
>>>>
>>>> local ok, val1, val2, val3 = coroutine.resume(...)
>>>> if ok then
>>>>  -- do something with 'val1', 'val2', 'val3'
>>>> else
>>>>  -- 'val1' is the error message, process it
>>>> end
>>>>
>>>>
>>>>
>>>>
>>> but what if I don't know the amount of multi return values?
>>>
>>>
>>
>>
>
> e, there are something like this Vim code?
> let a, b, c; d = [1,2,3,4,5,6,7] --> a = 1, b = 2, c = 3, d = [4,5,6,7]
>
> in a word, just use one structure/semantics to split a multi return
> value into two parts, and we can store each part of values.
>

function take3(a, b, c, ...) return a, b, c, {...} end
a, b, c, d = take3(1, 2, 3, 4, 5, 6, 7) --> a = 1, b = 2, c = 3, d = {4,5,6,7}