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Just modify the code from
 
module('json.rpc')
local json = require('json')
local http = require("socket.http")
to
 
local json = require('json')
local http = require("socket.http")
module('json.rpc')
 
 
 
2010-11-10


发件人: sagasw <sagasw@gmail.com>
发送时间: 2010-11-10 08:44
主 题: a naive issue about json4lua
收件人: lua-l@lists.lua.org


Hi,

When I try to use the json4lua, encounter a naive issue that make trouble for me.

I download the json4lua 0.9.30 from http://json.luaforge.net/
indeed the latest version is 0.9.50, but I don't think it is the point.

I just use lua for windows, and place the folder json under e:\Lua\5.1\lua\.
So under folder E:\Lua\5.1\lua\json, I could see 3 lua files "json.lua rpc.lua rpcserver.lua"

some testing code like:

----------------------------------------
json = require("json")
testString = [[ { "one":1 , "two":2, "primes":[2,3,5,7] } ]]
o = json.decode(testString)
table.foreach(o,print)
print ("Primes are:")
table.foreach(o.primes,print)

require ("json.rpc")
result, error = json.rpc.call("http://jsolait.net/testj.py","echo","Test echo!")
print(result)
----------------------------------------


and the result like:
----------------------------------------
one    1
primes    table: 00630588
two    2
Primes are:
1    2
2    3
3    5
4    7
lua: E:\lua\5.1\lua\json\rpc.lua:30: attempt to call global 'require' (a nil value)
stack traceback:
    E:\lua\5.1\lua\json\rpc.lua:30: in main chunk
    [C]: in function 'require'
    first.lua:8: in main chunk
    [C]: ?
>Exit code: 1


You could see the test for json returns correct result.
But failed to call rpc.lua, the rpc.lua looks like following, and failed part is the line "require('json')":

module('json.rpc')
local json = require('json')
local http = require("socket.http")

Could anyone tell me how to fix the issue? What should I do or make some setting change?
thanks,

------------------------------------------
blog: http://sunxiunan.com/
C++, Lua, living in Dalian
http://twitter.com/sagasw
------------------------------------------