yea it works but my mean is : test = "Test" if test then print("", "True") else print("", "False") end
now this code works in lua but if i set test = "" still it works because strings in lua have true value so "False" print never shown.
--- On Mon, 8/16/10, Luiz Henrique de Figueiredo <lhf@tecgraf.puc-rio.br> wrote:
From: Luiz Henrique de Figueiredo <lhf@tecgraf.puc-rio.br> Subject: Re: _expression_ statements To: "Lua list" <lua@bazar2.conectiva.com.br> Date: Monday, August 16, 2010, 1:32 PM
> for example i want in my interpreter this code works : > test = "Hello" > if test then > -- Do
Something > end
It already works in the stock interpreter, doesn't it?
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