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* On 2009-11-13 steve donovan <steve.j.donovan@gmail.com> wrote  :

> On Fri, Nov 13, 2009 at 3:02 PM, Andreas Krinke <andreas.krinke@gmx.de> wrote:
> > os.clock() uses clock() from time.h which returns used processor time,
> > not time since Lua started.
> 
> D:\downloads>lua -e "print(os.clock())"
> 0

Your program just used 0 seconds of processor time.

  ico@lapdoos:~$ lua -e "a=1; for i = 1, 1000000 do a=a+1 end; print(os.clock())"
  0.09

This process was using the CPU for 0.09 seconds

  ico@lapdoos:~$ lua -e "os.execute('sleep 1'); print(os.clock())"
  0

And this one, although running for 1 second, used 0 seconds of CPU time
as well. The os.execute() call blocks until the child process finishes,
and blocking system calls do not use the CPU.


-- 
:wq
^X^Cy^K^X^C^C^C^C