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On Fri, Nov 6, 2009 at 3:20 PM, zweifel <zweifel@gmail.com> wrote:Because it's only set by the Lua interpreter itself. But you can
> hey steve, that would be a better solution, but why my print(arg) returns
> nil? Ok, maybe I have not passed any arguments, but do I have to pass args
> in order to access the arg[0]??
create your own args table, make it global and access that from your
script.
E.g. in lua.c:
int narg = getargs(L, argv, n); /* collect arguments */
lua_setglobal(L, "arg");
where getargs() is
static int getargs (lua_State *L, char **argv, int n) {
int narg;
int i;
int argc = 0;
while (argv[argc]) argc++; /* count total number of arguments */
narg = argc - (n + 1); /* number of arguments to the script */
luaL_checkstack(L, narg + 3, "too many arguments to script");
for (i=n+1; i < argc; i++)
lua_pushstring(L, argv[i]);
lua_createtable(L, narg, n + 1);
for (i=0; i < argc; i++) {
lua_pushstring(L, argv[i]);
lua_rawseti(L, -2, i - n);
}
return narg;
}