Re: Using environment for OO

[David Given <dg@...>]

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Martin C. Martin wrote:
[...]
> My "new" function takes a table to use for the object, so it goes
> through it an calls setfenv() on each function[...]

But, assuming I've understood what you're talking about correctly, this
way you'll have to have a *different* function for every instance of the
object. So x.foo and y.foo cannot refer to the same function foo(), even
if x and y are instances of the same class.

[...]
> function MyClass.new(obj)

If I do:

o = { foo = function foo() end }
x = MyClass.new(o)
y = MyClass.new(o)

...then when x is created, o.foo's environment will be updated to point
to x; then when y is created, o.foo's environment will be updated to
point to y. Since x.foo == y.foo == o.foo, calling x.foo() will call the
method with y as the environment. I assume this isn't what you want?

(I could be misunderstanding what you mean here; I haven't used function
environments much beyond sandboxing.)

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