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Alexander Gladysh wrote:

If you can afford to corrupt one of the tables, you can optimize out
second loop (untested code):

function compareTables(t1, t2)
   -- all key-value pairs in t1 must be in t2
   for k, v in pairs(t1) do
       if t2[k] ~= v then return false end
       t2[k] = nil
   end
   return next(t2) == nil -- there must not be other keys in t2
end
Interesting idea. This time I have to do a non-destructive comparison, but it could be useful in other occasions.
(anyway, my question was more out of curiosity than for a real need of to-the-last-ns optimizazion). 

  Enrico