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>  >  for (int i = 0; i < 10; ++i)
>  >  {
>  >   if (i % 2)
>  >   {
>  >     continue;
>  >   }
>  >   printf("odd %d", i);
>  >  }
>  >
>  >  I treat continue in the first example as an another exit from the loop
>  >  iteration.
>
>  No it is not! The only exit point from the "for" loop above is the
>  condition "i<10".
>  "continue" simply causes to skip printf statement.

The only exit point from the *loop* is the condition "i < 10".
But continue is an extra exit point from a *single iteration* of the
loop -- that is, the code between its {}.

Alexander.