how can adding 2 numbers, converting it to a string, then pattern
matching it to "2" do anything useful? string.match returns either a
substring or nil. So, you'll get something non-nil if the result of
the addition contains the digit 2 in decimal. That's certainly not
what was requested?
e.g. take 10000 and 00100, no matching bits but
16 + 4 = 20, which contains "2"
without bit-wise operators in lua (e.g. XOR), you're going to need to
go through the digits one at a time I'm afraid...
Merick wrote:
Shmuel Zeigerman wrote:
Merick wrote:
I was wondering if there was any way - other than using a for loop
to iterate through each character - to use the string library to
compare two strings with representations of binary numbers and
tell whether or not any of the 1's in the strings are in the same
position?
Something like compare("11100", "00011") would return false and
compare("11100","00111") would return true
function compare(a,b)
a = tostring(tonumber(a) + tonumber(b))
return a:match"2"
end
Dangit, that's so simple I can't believe I didn't think of it myself!
Thanks
