RE: "Require" in a sandboxed environment

["Tom Miles" <Tom@...>]

I create multiple threads using lua_newthread(), all hanging off the
same state, which behaves thusly (from 5.1 manual) : "Creates a new
thread, pushes it on the stack, and returns a pointer to a lua_State
that represents this new thread. The new state returned by this function
shares with the original state all global objects (such as tables), but
has an independent execution stack."

I would therefore expect all packages to be shared amongst all the
threads.

-----Original Message-----
From: lua-bounces@bazar2.conectiva.com.br
[mailto:lua-bounces@bazar2.conectiva.com.br] On Behalf Of Duncan Cross
Sent: 09 August 2007 09:19
To: Lua list
Subject: Re: "Require" in a sandboxed environment

It looked to me like it uses multiple Lua threads within the same single
main state, not multiple main states - shouldn't they share the registry
and therefore loaded packages?

On 8/9/07, Nick Gammon <nick@gammon.com.au> wrote:
>
> On 02/08/2007, at 5:48 PM, Tom Miles wrote:
>
>
> > We know that the environment 1 code is called before environment 2, 
> > yet the results are the ouput is:
> > 1
> > nil
>
>
>  From what I can see of your code you are making multiple Lua states.
> When you "require" something it is like a '#include <file>' in C, you 
> get a copy of the code, not a shared state. Thus, the variables in 
> Utilities.lua are independent from one state to the next. Of course, 
> if you "require" something twice in a single Lua state then its 
> variables are shared, because it is being loaded into the same state.
>
> - Nick
>
 








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