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Jan Schütze wrote:


I wanted to ask if there is any way to escape (fast) all
magic characters in the string one wants to replace?


I don't know if it's fast enough for you, but this function
does what you want:

Lua 5.1.2  Copyright (C) 1994-2007 Lua.org, PUC-Rio

function plain2pat(s)

  s = string.gsub(s, "[[%%.*+?^$()-]", "%%%0")
  return (string.gsub(s, "%z", "%%z"))
end


allchars = ""
for i = 0, 255 do

  allchars = allchars .. string.char(i)
end

print(string.find(allchars, plain2pat(allchars)))

1       256

--
Aaron
http://arundelo.com

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