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http://lua-users.org/lists/lua-l/2006-08/msg00006.html



On 3/8/07, RJP Computing <rjpcomputing@gmail.com> wrote:


I am completely new to Lua so please bare with me as I learn. I am
tring to make a simple test application that just lets me embed lua
into a C++ application. I have been reading the "Programming in Lua"
book online and I just followed the example exactly as written. I am
using Lua v5.1.1, Windows XP-SP2, and MinGW to compile my application.
I am including the lua source right in my project and every time I run
my application I get this error:

    PANIC: unprotected error in call to Lua API (no calling environment)

I have tracked it down to the line:
    luaopen_io(L);
If I comment it out I can use the interpreter as I would expect.

Here is the source for main.cpp

int main( int argc, char* argv[] )
{
    char buff[256];
    int error;
    lua_State *L = lua_open();   /* opens Lua */
    luaopen_base(L);             /* opens the basic library */
    luaopen_table(L);            /* opens the table library */
    luaopen_io(L);               /* opens the I/O library */
    luaopen_string(L);           /* opens the string lib. */
    luaopen_math(L);             /* opens the math lib. */

    while (fgets(buff, sizeof(buff), stdin) != NULL)
    {
        error = luaL_loadbuffer(L, buff, strlen(buff), "line") ||
                lua_pcall(L, 0, 0, 0);
        if (error)
        {
            fprintf(stderr, "%s", lua_tostring(L, -1));
            lua_pop(L, 1);  /* pop error message from the stack */
        }
    }

    lua_close(L);
    return 0;
}

Any ideas?
--
Regards,
Ryan
RJP Computing