Re: function question

[David KOENIG <karhudever@...>]

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Terisquas Brothers wrote:
> a fast one: I'm trying to do this:
> 
> tab={
> 
> function b()
>   echo "hi!";
> end;
> 
> };
> 
> 
> but it fails. However
> 
> tab={
> 
> b=function()
>   echo "hi!";
> end;
> 
> };
> 
> works. Is this the intended way to work? I fail to see
> any reason to disallow the first one
> 
> 
> 
> 
> Happy new year! :)
> Kak
> 
> Send instant messages to your online friends http://uk.messenger.yahoo.com 
> 

When something is a member of a table, you need to say "foo = value".
This is why the first one doesn't work. Try this if you want a more
function-y syntax:

tab = {}
function tab.b()
  echo "hi!";
end;
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