Re: "continue" construct in Lua loops

[Philippe Lhoste <PhiLho@...>]

Javier Guerra a écrit :
> On Thursday 21 December 2006 8:21 am, Roberto Ierusalimschy wrote:
> > > Is there a more elegant way?
> > No :(  (At least you can be confident that the generated opcode is
> > as good as for a primitive continue ;)
>
> i guess both metalua's and token filter's wizards will soon present their 
> solutions.
>
> but this is not the first time this has been discussed. i beleive there was a 
> serious semantic problem; but i can't remember it now
>
> i'd really wish there was a 'continue' statement, in fact i've been using deep 
> if's, for me the 'break out of repeat' construct is an improvement!!

Yes, I frown as it was a kind of Faq, but since Leo came with a good 
solution, that is even marked as "efficient" by Roberto himself, no problem!
I will add this to my toolbox... ;-)

for i = 0, 9 do repeat
 if math.mod(i, 2) == 0 then break end
 print(i)
until true end

It has a look of "special loop with continue" syntax... :-)

--
Philippe Lhoste
--  (near) Paris -- France
--  http://Phi.Lho.free.fr
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