Re: Not able to access lua table values in C++

["jason zhang" <jzhang@...>]

To travel a table, use below codes:

    if(!lua_istable(L,-1))
    {
        return;
    }

    lua_pushnil(L);  /* first key */
    while (lua_next(L, -2) != 0) {
        /* uses 'key' (at index -2) and 'value' (at index -1) */ 
        //add your own code to get the key and value
     
        /* removes 'value'; keeps 'key' for next iteration */
        lua_pop(L, 1);
    }


----- Original Message ----- 
From: "Gokul N" <gokul.n@hotmail.com>
To: <lua@bazar2.conectiva.com.br>
Sent: Thursday, September 28, 2006 12:06 PM
Subject: Not able to access lua table values in C++


> Hi,
> 
> Iam trying to access the lua table values in c++,Iam not able to print the 
> values.
> here is the code of what iam doing.
> 
> -- A Table to be called from c++
> -- imageTable.lua
> imag = {"bg1", "bg2", "bg3", "bg4","bg5"}
> print("done")
> 
> 
> //   sample code
> 
> // luatable.cpp : Defines the entry point for the console application.
> //
> 
> #include "stdafx.h"
> #include <iostream>
> using namespace std;
> 
> extern "C" {
> #include "lua.h"
> #include "lualib.h"
> #include "lauxlib.h"
> }
> 
> // the Lua interpreter
> lua_State* L;
> 
> //global variable
> size_t* len;
> 
> 
> // A function to access a lua table in c++
> int access_luaTable(lua_State* L)
> {
> // temp variable
> const char* temp;
> 
> //get the imag lua table from imageTable.lua
> lua_getglobal( L, "imag" );
> if( lua_istable( L, -1 ) )
> {
> switch ( lua_type( L, lua_gettop( L ) ) )
> {
> case LUA_TTABLE:  std::cout << "script returned a table" << std::endl; 
> break;
> default: std::cout << "script returned unknown param" << std::endl; 
> break;
>         }
> 
> //int idx=lua_gettop( L );
> //lua_gettable(L, idx);
> lua_gettable( L, -1 );
> //lua_pushvalue(L,2);
> lua_rawget(L,-1);
> 
> //lua_pushnil(L);  /* first key */
> while (lua_next(L, -1) != 0) {
>         // `key' is at index -2 and `value' at index -1
>         printf("%s - %s\n",lua_typename(L, lua_type(L, -2)), 
> lua_typename(L, lua_type(L, -1)));
> lua_pop(L, 1);  /* removes `value'; keeps `key' for next iteration */
> }
> return 0;
> }
> if( lua_isnil( L, -1 ) )
> {
> return 0;
> }
> 
> 
> return 0;
> }
> 
> 
> int main ( int argc, char *argv[] )
> {
> /* initialize Lua */
> L = lua_open();
> 
> /* load Lua base libraries */
> luaL_openlibs( L );
> 
> /* load the script */
> luaL_dofile( L, "imageTable.lua" );
> 
> /* call the a function */
> access_luaTable( L );
> 
> /* cleanup Lua */
> lua_close( L );
> 
> /* pause */
> printf( "Press enter to exit? );
> getchar();
> 
> return 0;
> }
> 
> can somebody tell me what i should be doing to print values..
> 
> regards
> Gokul
> 
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