RE: question about table elements

["Chris Poole" <chris@...>]

Hi Ryan,

I believe what you are looking for is

print(inodes[tmp]) 

As this uses the contents of temp as the key, rather than inodes.tmp
which would be equivalent to inodes['tmp']

Best regards,
Chris

> -----Original Message-----
> From: lua-bounces@bazar2.conectiva.com.br 
> [mailto:lua-bounces@bazar2.conectiva.com.br] On Behalf Of Ryan Cresawn
> Sent: 10 August 2006 16:31
> To: Lua list
> Subject: Re: question about table elements
> 
> Lua list,
> 
> I think it's important that I explain the problem I'm trying 
> to solve a little more clearly.  I am writing a Lua script 
> that is designed to monitor a log file and mail me the new 
> content when it is found.  The script is designed to run from 
> cron and it is necessary that it account for the possibility 
> that the log could be rotated.
> 
> The real code which is similar to 't2' in the example is a 
> persistent table that looks like this:
> 
> db {
>    ["inode"] = "2340691",
>    ["pos"] = 9,
> }
> 
> The 't1' equivalent is the output of 'ls -i1 /var/log'.  I 
> grab the inode and the file and enter them into a table 
> called 'inodes'.  The key is the inode and the value is the 
> filename.  A short version of the 'inodes' table looks like this:
> 
> inodes {
>    ["2299409"] = "kernlog",
>    ["2340691"] = "kernlog.0",
> }
> 
> My goal is to view the value stored in 'db.inode' and then 
> find the filename to open in the 'inodes' table.  I had hoped 
> to do something like this:
> 
> tmp = db.inode
> print(tmp)         --> 2340691
> print(inodes.tmp)  --> nil
> 
> This fails and I have not come up with a way to circumvent 
> it.  Any ideas?
> 
> Ryan
> 
> 
> On Thu, Aug 10, 2006 at 10:48:46AM -0400, Ryan Cresawn wrote:
> > Lua list,
> > 
> > I'm having a difficult time accessing table elements and I would 
> > appreciate some help.  The code below is test code but it 
> behaves the 
> > same way that my larger program does.
> > 
> > -- begin example --
> > 
> > t1 = {
> >    ["a"] = 1,
> >    ["b"] = 2,
> >    ["c"] = 3,
> > }
> > 
> > t2 = {
> >    ["x"] = "a",
> > }
> > 
> > tmp = t2.x
> > print(tmp)     --> a
> > print(t1.tmp)  --> nil
> > 
> > -- end example --
> > 
> > How could I achieve the goal of using the value stored in 't2.x' to 
> > access 't1.a'?  I suspect I'm overlooking something simple 
> and would 
> > appreciate any advice you may offer.
> > 
> > Ryan
> 
> 
> 
>