Re: Best strategy to check all elements of a table

[Jose Marin <jose_marin2@...>]

Good, that's what I needed!
Thanks!


--- Glenn Maynard <glenn@zewt.org> escreveu:

> On Mon, May 29, 2006 at 06:57:58PM +0000, Jose Marin
> wrote:
> > I don't have to check collisions twice, only one
> time
> > for each pair of objects.
> > 
> > In pseudocode:
> > 
> > for obj1 = list.first to list.end do
> >    for obj2 = list.first to list.end do
> >     
> >       if obj1.collideWith(obj2) then 
> >         obj1.DoSomething(obj2)
> >       end
> >    end
> > end
> 
> More of an algorithm question than Lua, but you
> probably want (using your
> pseudocode):
> 
> for obj1 = list.first to list.end do
>    for obj2 = obj1+1 to list.end do
>       if obj1.collideWith(obj2) then 
>         obj1.DoSomething(obj2)
>       end
>    end
> end
> 
> or in Lua:
> 
> list = { "a", "b", "c", "d", "e" }
> for k, v in next, list, nil do    -- same as
> pairs(list)
>   for k2, v2 in next, list, k do  -- like
> pairs(list), but start at next(k)
>     print(v .. ", " .. v2);
>   end
> end
> 
> -- 
> Glenn Maynard
> 



		
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