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Hello, Does
any one know whether it is safe to use lua_xmove() when both the source and
destination states represent the same state and, if it is safe, does this
operation leave the stack unchanged (as intuitively expected)? <background
info> I am
implementing a Lua debugger for one of our applications. In my implementation, a
script is run as a coroutine by invoking lua_resume() while being debugged and
run on the main Lua state with lua_pcall() when it’s not being debugged. The
decision to debug the script or not is done at run-time by reading from a
properties file. As the
C-side (actually Delphi-side) code uses lua_xmove() in a few places, I could keep
the code uncluttered by simply ignoring the fact that the ‘from’
and ‘to’ arguments of lua_xmove() are one and the same state. The
two states would coincide when the script is not being debugged and I would expect
that such an operation would result in no changes made to the stack. </background
info> Thanks |