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And we cant set the __len metamethod on a table to change this
behaviour. Bummer.


On 3/6/06, Couwenberg, Wim <> wrote:
> > it
> > would be convenient (and consistent) if the # operator
> > provided the following behaviour (this is the assertion):
> >
> > "# provides the same number as the number of iterations
> > provided by ipairs".
> Convenient maybe, but also more expensive.  The current # implementation
> is O(log(N)) where N is the number of entries in the array part.  The
> rule above would make that O(N) in general.  You can use table.maxn to
> find the highest overall numerical index (ignoring gaps).  This is of
> course also more expensive than applying #.
> --
> Wim
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