Re: How to format a number with thousandth separators?

[Zakaria <z4k4ri4@...>]

On 1/26/06, PA <petite.abeille@gmail.com> wrote:

> On Jan 25, 2006, at 09:40, Zakaria wrote:

> > I'm a Lua newbie. What is the best way to do it?

> Very brutal, there must be a better way :)

> function self:formatNumber( aNumber, aLocale )
>          if aNumber ~= nil then
>                  local aString = tostring( math.floor( aNumber ) )
>
>                  if aString:len() > 3 then
>                          aString = aString:reverse()
>                          aString = aString:gsub( "(%d%d%d)", "%1," )
>                          aString = aString:reverse()
>
>                          if aString:sub( 1, 1 ) == "," then
>                                  aString = aString:sub( 2 )
>                          end
>                  end
>
>                  return aString
>          end

>          return nil
> end

Is that lua? what version? I use

> Some alternatives:

> http://www.bigbold.com/snippets/posts/show/693
> http://www.rubygarden.org/ruby?NumericFormat

> Cheers

> --
> PA, Onnay Equitursay
> http://alt.textdrive.com/

Wassallam,


-- Zakaria
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