Re: AW: Size of a non numerical indexed table

[Brian Weed <bw@...>]

Won't this do what he wants?

function TableSize(t)
   local i=0
   for k in pairs(t) do i = i + 1 end
   return i
end

Brian


steffenj wrote:

> hmmm, quick and dirty solution:
>
> local count = 0
> table.foreach(table, function(i, v)
> 	-- don't count numerical indices:
> 	if type(i) == "string" then
> 		count = count + 1
> 	end
> end
>
> but it's definetely better to use a metatable and count all the string
> indizes when values are assigned to table indizes
>
> i haven't used metatables so far but the basics are to check, on assignment,
> wether the index is a string and wether the value is nil (delete index) or
> not (new index) and based on that, update a counter in the table
>
> i hope someone else can give an example...
>
> -----Ursprüngliche Nachricht-----
> Von: lua-bounces@bazar2.conectiva.com.br
> [mailto:lua-bounces@bazar2.conectiva.com.br] Im Auftrag von Jose Marin
> Gesendet: Mittwoch, 31. August 2005 22:06
> An: lua@bazar2.conectiva.com.br
> Betreff: Size of a non numerical indexed table
>
> Well, I think that the subject tells my question!
>
> If it's a numerical indexed table, I can use
> table.getn, but if the table is indexed by names, how
> to get it's size?
>
> Thanks!
>
>
>
>
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