RE: Calling a function in a table from C++ without loosing 'self'

["Framework Studios: Hugo" <hugo@...>]

Thanks for the quick reply!

 

If I change it to lua_call(VM, 1, 0) the interpreter goes into error and stops executing my script.

 

So if I do:

 

msg("Will show")
GameObject:start()

msg("Won't show")

...the second message won't show. (note: 'msg' is a function to simply show a message box).

 

Shouldn't I somehow push 'self' onto the stack before doing the call? Is this the same as pushing the metatable onto the stack? (just guessing here :)

 

    Thanks again,

        Hugo

 

 

 -----Original Message-----
From: lua-bounces@bazar2.conectiva.com.br [mailto:lua-bounces@bazar2.conectiva.com.br]On Behalf Of Russell Y.Webb
Sent: woensdag 8 juni 2005 12:09
To: Lua list
Subject: Re: Calling a function in a table from C++ without loosing 'self'

On Jun 8, 2005, at 8:58 PM, Framework Studios: Hugo wrote:

I'm trying to call a function called 'init' in a table from C++. Currently this is what I've got:
 
int cGameObject::start(lua_State *VM)
{
// first get the table
 lua_pushstring(VM, m_TableName);        // m_TableName = "GameObject" in this example
 lua_gettable(VM, LUA_GLOBALSINDEX);
// get the 'init' function from the table
 lua_pushstring(VM, "init");
 lua_gettable(VM, -2);
// call the function
 lua_call(VM, 0, 0);
 
return 0;
}

Try using
lua_call(VM, 1, 0)
since you have 1 argument to pass (self is the first argument).

Note t:f() is semantically the same as t.f(t)

Hope that helps,
Russ