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The type-checking won't work in your example because foo might get redefined
before being called by foobar.


on 11/9/04 9:59 PM, Quinn Tyler Jackson at wrote:

> This could also be used for simple type checking:
> function foo() returns string
> return "10";
> end
> function foobar() returns number
> return foo(); // illegal, since foo returns string
> end