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- Subject: Re: (lua_State *const L)
- From: Ben Sunshine-Hill <sneftel@...>
- Date: Tue, 14 Sep 2004 10:47:35 -0700
Each coroutine has a new lua_State*, which is created when the
coroutine is created and destroyed when the coroutine is garbage
collected. So if those coroutines call into the C side, the new
lua_State* will show up there. For C functions exported to Lua, use
whatever lua_State is passed into them, and make sure that functions
it calls do as well.
By default, all lua_States have the same registry. In terms of
performing the callback, you'd probably want to use the main
lua_State, since any others will be yielded and should not have
function calls performed on them.
On Tue, 14 Sep 2004 13:03:44 +0100, Adam D. Moss <firstname.lastname@example.org> wrote:
> One of my sanity asserts in the C api I export to
> Lua is that (sengine == L), where 'sengine' is the
> lua state originally returned by lua_open() and 'L'
> is the state passed as parameter to C functions
> called by Lua.
> This has usually been a safe assertion, but some recent
> insignificant tweaks to my Lua-side code have sometimes
> (temporarily!) made (sengine != L) for some calls, so I think
> that this assumption is not a good one. This is Lua 5.0.2.
> Under what circumstances might a new lua state pointer
> be used? I don't use threads, but I do use coroutines;
> is this symptomatic of a lua->C call from a
> Will my original 'sengine' always be good, up until a
> lua_close()? The real reason I'm concerned about this
> varying *L pointer is that my lua app registers callbacks
> (funcs put in the registry) with the C-side, and then the
> C-side calls them rather later. BUT, the C-side calls
> them with the original 'sengine', not the L* at the time
> the callback was registered. Which of the two lua_States
> should I use the registry of (I assume this doesn't matter),
> but more importantly which of the two lua_States should I
> perform the callback with?