Re: segv in ldo.c:line 284 for lua version 5.0

[Roberto Ierusalimschy <roberto@...>]

Probably you got a stack overflow. Each call

        status = report(l, lcall(l, 0, 1));

leaves one result on the stack (assuming that `lcall' is `lua_call'). If
you do not pop it from the stack, the loop will overflow.

-- Roberto