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I changed it and got things to work. Here is what the function looks like now: 

function dep:remove( _name )
   for i = 1, table.getn(self.deps), 1
   do
       if self.deps[i]["name"] == _name
       then
           a = i
       end
   end
   table.remove(self.deps,a)
end

Thanks for the help

D Burgess wrote:


May or may not be your problem but,
from the manual -

All three control expressions are evaluated only once,
before the loop starts.

Note the once.

After the first table.remove, the second parameter of
the 'for' will be a number larger than the number of table entries. 
+++++++++++++++++++++++++++++++++

Hi,
I am having a problem with tables. The culprit is the following function: 

function dep:remove( _name )
  for i = 1, table.getn(self.deps), 1
  do
      if self.deps[i]["name"] == _name
      then
           table.remove(self.deps, i)
      end
  end
end

When I call this function I get the following error:

lua: depends.lua:22: attempt to index field `?' (a nil value)
stack traceback:
      depends.lua:22: in function `remove'
      depends.lua:37: in main chunk
      [C]: ?
I checked and i is a valid element in that table. This function does seem to work when i is the last element of the table. I also tried typing a number in directly. When I replaced table.remove(self.deps, i) with table.remove(self.deps, 1) things also failed. Then I tried taking it out of the for loop, and everything worked. 

Can someone help me fix this?

Mike Atamas
aelfgar@aelfgar.com