Re: why no "continue" statement for loops?

[RLake@...]

> Notice that you only get this behavior when you do tail calls. In Lua,
> this means "return f(...)".  None of these apparently equivalent forms
> works:

>   f(); return
>   return x, f()
>   return x or f()

> -- Roberto

But this one works :)

> function always(x) return function() return x end end
> function add(i, j) return (i == 0 and always(j) or add)(i - 1, j + 1) 
end
> =add(1, 1000000)
1000001