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>That doesn't work because + is not unambiguously unary. So:
>    a = f
>    +(b or c)(g)
>is still ambiguous. In any event, I find the use of + as an identity
>operator a bit irritating, for some reason. Maybe it's my anti-Perl bias. I
>prefer + to be unambiguously binary.

That's what it is in Lua: there's no unary +. There's a unary -, though.