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>If s == "a.b" you'll have to escape it before using in the
>pattern:
>
>s = gsub (s, "(%p)", "%%%1")
>
>	So, "a.b" will be "corrected" to "a%.b".  This is required for
>every solutions given (mine, Roberto's ...).

Yes, I thought of that, but it never hurts to think twice :-)

  Enrico