Re: [PATCH] lstrlib and match() \0 in pattern strings

[Vaughan McAlley <ockegheim@...>]

> While I had no problems with that in the past, I just spotted the pattern of the matching does treat the first \0 as the end of the pattern.

Ah, so that’s why "%z" exists...

I think the following would "pre-process" an arbitrary binary string,
making it ready to be searched for in another arbitrary binary string:

-- searching for s in another string...
s = string.gsub(s, "[%z%p]", function(c)
    if c == "\0" then
        return "%z"
    else
        return "%" .. c
    end
)

Vaughan