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Thanks for the quick reply Ketmar, and apologies to all for the noise:
turns out I was wrong - the code I showed does work - the problem was that the module didn't compile elsewhere, and the error message was a symptom of that. I did think I'd seen the problem before - perhaps I'd made the same mistake then too. 

cheers,
Geoff

On 6/09/2007, at 8:08 PM, Ketmar Dark wrote:


hello, Geoff Leyland <geoff_leyland@fastmail.fm>.

On Thu, 6 Sep 2007 19:52:59 +1200
Geoff Leyland <geoff_leyland@fastmail.fm> wrote:


Does anyone have any suggestions as to how to achieve the same thing
(work out if we're being run as someone else's module or as a top-
level script) a better way?


here's my code. it works in Lua 5.1+

function kmodule (module, name)
  if type(package.loaded[name]) == "userdata" then
    -- emulate "module"
    module._M = module;
    if type(name) == "string" then
      module._NAME = name;
      local pkg = name:match("^(.-%.)[^%.]*$") or "";
      module._PACKAGE = pkg;
    end;
    return module;
  else return false;
  end;
end;

and usage:
local mymodule = {};

function mymodule.MyFunc ()
...
end;

...
...

if kmodule(mymodule, ...) then return mymodule; end;


and then:
local mymodule = require "mymodule";

i don't like to pollute global namespace. %-)