Re: String pattern for chinese word

[Rena <hyperhacker@...>]

On Mon, Apr 16, 2012 at 07:10, Choonster TheMage
<choonster.2010@gmail.com> wrote:
> On Mon, Apr 16, 2012 at 10:55 PM, jiang yu <yu.jiang.163@gmail.com> wrote:
>> Hi all!
>>  s = [[ '\xe8\x8b\xb1\xe9\x9b\x84\xe6\x95\x91\xe7\xbe\x8e','id','哈哈','6' ]]
>>  for i in string.gmatch(s,"'(%w+)'") do
>>    print(i)
>>  end
>> output is:
>> id
>> 6
>>  How can I get the all four words?
>>
>>
>> mos
>>
>
> I believe %w only matches letters of the Latin alphabet and numbers.
> One way to capture all four words would be to use the %b token:
>
>  s = [[ '\xe8\x8b\xb1\xe9\x9b\x84\xe6\x95\x91\xe7\xbe\x8e','id','哈哈','6' ]]
>  for i in string.gmatch(s,"%b''") do
>   i = i:match("'(.+)'")
>   print(i)
>  end
>

The manual specifies that %b requires two *distinct* characters. In
this case you'd want something like: '(.-)'

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